A.fff\(4\frac{3+0.07}{11.092}\)/fff
B.fff\(\frac{\sqrt82-1.7^2}{\sqrt34}\)/fff
C.fff\(\frac{9978.4-0.0083}{101^2}\)/fff
D.fff\(\sqrt{143}·\sqrt[3]{7}\over{24.034}\)/fff
我的答案：
