If the numbersfff\(\frac{19}{36},\frac{5}{11},\frac{12}{25},\frac{6}{11},and \frac{8}{18}\)/fff, andfff\(\frac{8}{18}\)/fffwere arranged from least to greatest, which number would be in the middle?
A.$$\frac{19}{36}
B.$$\frac{12}{25}
C.$$\frac{6}{11}
D.$$\frac{5}{11}
E.$$\frac{8}{18}
